Answer
(a) $CH_2ClCOO^-$
(b) $IO_4^-$
(c) $H_2PO_4^-$
(d) $HPO_4^{2-}$
(e) $PO_4^{3-}$
(f) $HSO_4^-$
(g) $SO_4^{2-}$
(h) $IO_3^-$
(i) $SO_3^{2-}$
(j) $NH_3$
(k) $HS^-$
(l) $S^{2-}$
(m) $ClO^-$
Work Step by Step
The conjugate base of an acid is, basically, the acid when a $(H^+)$ is removed.
Therefore, we should follow these steps:
1. Remove a Hydrogen from the compound.
2. Subtract 1 from its charge.
