Answer
(a) = $3.80 \times 10^{-3}$
(b) = $6.17 \times 10^{-12}$
(c) = $1.10 \times 10^{-7}$
(d) = $1.00 \times 10^{-15}$
Work Step by Step
Use the equation:
$[H^+] = 10^{-pH}$
To find the concentrations.
(a) $[H^+] = 10^{-2.42} = 3.80 \times 10^{-3}$
(b) $[H^+] = 10^{-11.21} = 6.17 \times 10^{-12}$
(c) $[H^+] = 10^{-6.96} = 1.10 \times 10^{-7}$
(d) $[H^+] = 10^{-15} = 1 \times 10^{-15}$
