Chemistry 12th Edition

Published by McGraw-Hill Education
ISBN 10: 0078021510
ISBN 13: 978-0-07802-151-0

Chapter 1 - Chemistry: The Study of Change - Questions & Problems: 1.35

Answer

a) $1.1\times10^5m$ b) $7.87\times10^{-1}g$ c) $1.654\times10^1 cm$ d) $1.4\times 10^6 cm^3$

Work Step by Step

(a) 5.6792 m + 0.6 m + 4.33 m 5.6792 m = 4 d.p. 0.6 m = 1 d.p. 4.33 m = 2 d.p. 5.6792 m + 0.6 m + 4.33 m= 10.6092 m $=1.06092\times10^5$ $=1.1\times10^5m$ 1 d.p. (b) 3.70 g - 2.9133 g 3.70 g = 2 d.p. 2.9133 g = 4 d.p. 3.70 g - 2.9133 g = 0.7867 $=7.867\times10^{-1}g$ $=7.87\times10^{-1}g$ 2 d.p. (c) 4.51 cm X 3.6666 cm 4.51 cm = 3 s.f. 3.6666 cm = 5 s.f. 4.51 cm X 3.6666 cm = 16.536366 cm $= 1.6536366\times10^1 cm$ $=1.654\times10^1 cm$ 3 s.f. (d) $3 x 10^4 g = 1 d.p. ; 1 s.f.$ $6.827 g = 3 d.p. ; 4 s.f.$ $0.043 cm^3 = 3 d.p. ; 2 s.f.$ $0.021 cm^3 = 3 d.p. ; 2 s.f.$ $(3 x 10^4 g + 6.827 g)/(0.043 cm^3 — 0.021 cm^3)$ $3 x 10^4 g + 6.827 g= 30006.827 = 30006.8 g$ 1 d.p. $0.043 cm^3 — 0.021 cm^3=0.022cm^3$ 3 d.p. $\frac{30006.8}{0.022}\approx1363945.4545454545454545$ $=1.3639454545454545454545\times 10^6$ $=1.4\times 10^6 cm^3$
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