Chapter 1 - Chemistry: The Study of Change - Questions & Problems - Page 31: 1.43

$8.3 \ min$

$(1 mi = 1609.34 \ m)$ $93\times10^6 mi =(93\times10^6)\times1609.34 \ m$ $V=\frac{d}{t}$ $t=\frac{d}{V}$ $=\frac{(93\times10^6)\times1609.34}{3.00 x 10^8 }$ $=498.8954s\div60min$ $=\approx8.3149233333333333min$ $=8.3min$