Answer
$\theta = 135^\circ$
Work Step by Step
For $\sin\theta = \frac{\sqrt{2}}{2}$ and $\cos\theta = -\frac{\sqrt{2}}{2}$,
$\theta$ terminated in the 2nd quadrant, hence,
$\theta= arccos(-\frac{\sqrt{2}}{2})$
$\theta = 135^\circ$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 8 - Section 8.1 - Complex Numbers - 8.1 Problem Set - Page 427: 97
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