Answer
$\theta = 150^\circ$
Work Step by Step
For $sin\theta = \frac{1}{2}$ and $\theta$ terminates in the 2nd quadrant QII,
$\theta= arcsin(\frac{1}{2})$
$\theta = 150^\circ$ (since $\theta$ terminates in the 2nd quadrant QII)
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 8 - Section 8.1 - Complex Numbers - 8.1 Problem Set - Page 427: 98
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