Answer
$-30+24i$
Work Step by Step
$z_{3}(z_{1}-z_{2})$
=$(4+5i)[(2+3i)-(2-3i)]$
=$(4+5i)(2-2+3i+3i)$
=$(4+5i)(6i)$
=$24i+30i^{2}$
=$24i+30(-1)$
=$-30+24i$
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