Answer
$-7+22i$
Work Step by Step
$z_{3}z_{1}$
=$(4+5i)(2+3i)$
=$4(2+3i)+5i(2+3i)$
=$8+12i+10i+15i^{2}$
=$8+22i+15(-1)$
=$-7+22i$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 8 - Section 8.1 - Complex Numbers - 8.1 Problem Set - Page 426: 78
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