Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 7 - Section 7.5 - Vectors: An Algebraic Approach - 7.5 Problem Set - Page 404: 28

Answer

$|V|=\sqrt{73}.$

Work Step by Step

The magnitude of a vector is given by the possible square root of the sum of the squares of its horizontal and vertical components. Let $V=\langle -8,-3\rangle.$ Then \begin{align*} |V|&=\sqrt{(-8)^{2}+(-3)^{2}}\\ &=\sqrt{64+9}\\ &=\sqrt{73}. \end{align*} Hence, $|V|=\sqrt{73}.$
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