Chapter 7 - Section 7.5 - Vectors: An Algebraic Approach - 7.5 Problem Set - Page 404: 38

$\frac{1}{2}V=(3,4)$ $-V=(-6,-8)$ $4V=(24,32)$

Remember to use the coefficients before I and J after that it should look like this below $V=(6,8)$ $\frac{1}{2}V=(\frac{1}{2}(a),\frac{1}{2}(b))$ $\frac{1}{2}V=(3,4)$ $-V=(-a,-b)$ $-V=(-6,-8)$ $-V=(-6,-8)$ $4V=(4(a),4(b))$ $4V=(4(6),4(8))$ $4V=(24,32)$