Answer
$\sin{7x}$
Work Step by Step
$\sin{(A-B)} = \sin{A} \cos{B} - \cos{A} \sin{B}$
$\therefore \sin{8x} \cos{x} -\cos{8x} \sin{x} = \sin{(8x-x)} = \sin{7x}$
Trigonometry 7th Edition
by McKeague, Charles P.; Turner, Mark D.
Published by
Cengage Learning
ISBN 10:
1111826854
ISBN 13:
978-1-11182-685-7
Chapter 5 - Section 5.2 - Sum and Difference Formulas - 5.2 Problem Set - Page 289: 32
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