Answer
$1$
Work Step by Step
$\tan{(A+B)} = \dfrac{\tan{A}+\tan{B}}{1- \tan{A} \tan{B}}$
$3 = \dfrac{\tan{A}+0.5}{1- 0.5\tan{A} }$
$3- 1.5 \tan{A} = 0.5+ \tan{A}$
$2.5 = 2.5 \tan{A}$
$\tan{A} = 1$
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