Answer
The equation is not an identity.
A counterexample: $\theta=0.$
Work Step by Step
Graphing utility used: online calculator, desmos.com.
(see below)
The graphs of the two expressions are not equal,
implying that the equation is not an identity.
A counterexample is $\theta$=0, for which
LHS=$1+1=2$
RHS=$0\cdot 0=0$
LHS$\neq$RHS, so the equation is not an identity.