Trigonometry 7th Edition

Published by Cengage Learning
ISBN 10: 1111826854
ISBN 13: 978-1-11182-685-7

Chapter 5 - Section 5.1 - Proving Identities - 5.1 Problem Set - Page 280: 73

Answer

Counterexample: $\theta=\pi$ (sample answer)

Work Step by Step

The LHS is a POSITIVE square root... so we look for a $\theta$ that produces a negative RHS. For example, if $\theta=\pi,$ $RHS=0+(-1)=-1$ LHS is positive, RHS is negative. They can't be equal, so the identity is not valid.
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