Answer
0.9879
Work Step by Step
to solve the given problem formula required is
$\sin(LT_{1})\sin(LT_{2})+\cos(LT_{1})\cos(LT_{2})\cos(LN_{1}-LN_{2})$
to calculate $ LT_{1}$
$ LT_{1} = (35+{\frac{51.449}{60}})^{\circ}$
$ LT_{1} = 35.8574^{\circ}$
$ LT_{1} = (35.8574 \times (\frac{\pi}{180}))$ radian
$ LT_{1} = 0.6258$
other angles can be calculated in similar way
$ LT_{2} = 0.6353$
$ LN_{1} = 0.2526$
$ LN_{2} = 0.4447$
so from above value calculation
$\sin(0.6258)\sin(0.6353)+\cos(0.6258)\cos(0.6353)\cos(-0.1912)$ =0.9879
thus the final answer is 0.9879