Answer
$\sec\theta=-\sqrt 2$, $\sin\theta=\frac{\sqrt 2}{2}$,
$\tan\theta=-1$, $\cot \theta =-1$ and $\csc\theta=\sqrt 2$
Work Step by Step
$\sec\theta=\frac{1}{\cos\theta}=-\frac{2}{\sqrt 2}=-\sqrt 2$
$\sin^{2}\theta=1-\cos^{2}\theta=1-\frac{2}{4}=\frac{1}{2}$
Since $\theta$ terminates in QII, $\sin\theta$ is positive.
$\sin\theta=\frac{1}{\sqrt 2}=\frac{\sqrt 2}{2}$
$\tan\theta=\frac{\sin\theta}{\cos \theta}=-1$
$\cot \theta =\frac{1}{\tan\theta}=-1$
$\csc\theta= \frac{1}{\sin\theta}=\sqrt 2$
