Answer
$|\textbf{V}_{x}|=900\,ft/s$
$|\textbf{V}_{y}|=1600\,ft/s$
Work Step by Step
Magnitude of the horizontal component $|\textbf{V}_{x}|=|\textbf{V}|\cos\theta=1800\,ft/s\times\cos 60^{\circ}=900\,ft/s$
Magnitude of the vertical component
$|\textbf{V}_{y}|=|\textbf{V}|\sin\theta=1800\,ft/s\times\sin 60^{\circ}=1600\,ft/s$
