Chapter 2 - Section 2.5 - Vectors: A Geometric Approach - 2.5 Problem Set - Page 106: 22

$\textbf{V}_{x}=367$ $\textbf{V}_{y}=110$

$\textbf{V}_{x}=|\textbf{V}|\cos\theta=383\times\cos(16^{\circ}40')=383\times\cos(16\frac{2}{3})^{\circ}$ $=383\times\cos(\frac{50}{3})^{\circ}=367$ $\textbf{V}_{y}=|\textbf{V}|\sin\theta=383\times\sin(16^{\circ}40')=383\times\sin(\frac{50}{3})^{\circ}=110$