Statistics for the Life Sciences (5th Edition)

Published by Pearson
ISBN 10: 0-32198-958-9
ISBN 13: 978-0-32198-958-1

Chapter 2 - Description of Sample and Populations - Exercises 2.3.1 - 2.3.14 - Page 44: 2.3.5

Answer

$y ̅ =293.8$ $y ̃=283$

Work Step by Step

$y ̅ =\frac{∑y_i}{n}=\frac{366+327+274+292+274+230}{5}=\frac{100}{5}=293.8$ Position of the median: $0.5(n+1)=0.5(6+1)=3.5$ That is, for a sample of size 6, the median is mean between the values of the third and the fourth observations. In the given sample it is $\frac{274+292}{2}=283$.
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