Statistics for the Life Sciences (5th Edition)

Published by Pearson
ISBN 10: 0-32198-958-9
ISBN 13: 978-0-32198-958-1

Chapter 2 - Description of Sample and Populations - Exercises 2.3.1 - 2.3.14 - Page 44: 2.3.7

Answer

Mean: $y ̅ =3.492~lb/day$ Median: $y ̃=3.36~lb/day$

Work Step by Step

$y ̅ =\frac{∑y_i}{n}=\frac{3.89+3.51+3.97+3.31+3.21+3.36+3.67+3.24+3.27}{9}=\frac{31.43}{9}=3.492$ The sample in ascending order: 3.21, 3.24, 3.27, 3.31, 3.36, 3.51, 3.67, 3.89, 3.97 Position of the median: $0.5(n+1)=0.5(9+1)=5$ That is, for a sample of size 9, the median is the value of the fifth observation in ascending order. In the given sample it is 3.36.
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