Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 6 - Normal Probability Distributions - 6-4 Sampling Distributions and Estimators - Page 276: 10

Answer

a) .667 b) (4,4); 0 (5,5); 1 (9,9); 1 (4,5); .5 (4,9); .5 (5,4); .5 (5,9); 1 (9,4); .5 (9,5); 1 c) .667 d) Yes

Work Step by Step

a) We use the equation for probability to find: $P=\frac{number\ of\ desired\ outcomes}{total\ number\ of\ outcomes}$ $P = \frac{2}{3}=.667$ b. The odds of all of the events is the same: 1/9. Thus, we use the same equation as above to find the percentage of odd numbers: (4,4); 0 (5,5); 1 (9,9); 1 (4,5); .5 (4,9); .5 (5,4); .5 (5,9); 1 (9,4); .5 (9,5); 1 c) We find that the mean is: $=(4/9)+(.5)(4/9)=.667$ d) The sample proportion is unbiased, for the results to part a and part c are identical.
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