Essentials of Statistics (5th Edition)

Published by Pearson
ISBN 10: 0-32192-459-2
ISBN 13: 978-0-32192-459-9

Chapter 6 - Normal Probability Distributions - 6-4 Sampling Distributions and Estimators - Page 276: 14

Answer

a) 0, 4/16 24.5, 2/16 2, 2/16 50, 2/16 40.5, 2/16 4.5, 2/16 72, 2/16 b) 24.2 c) Yes

Work Step by Step

a. We know there are 4 numbers, so there are $4^2=16$ ways to combine them. Combining the values with the same sample variances, we obtain the following: Sample variance, probability: 0, 4/16 24.5, 2/16 2, 2/16 50, 2/16 40.5, 2/16 4.5, 2/16 72, 2/16 b. We know the following equation for sample variance: $\sigma^2 = \frac{\Sigma(x-\bar{x})^2}{n}$. Using this as well as the population variance, we see that the sample and population variances are both 24.2. (To verify, it is the easiest to use a program such as Microsoft Excel.) c. The population variance is unbiased, for it is equal to the sample variance.
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