Elementary Statistics: Picturing the World (6th Edition)

Published by Pearson
ISBN 10: 0321911210
ISBN 13: 978-0-32191-121-6

Chapter 5 - Normal Probability Distributions - Review Exercises - Page 289: 59

Answer

a) $P(x < 30,000)$ = 0.1685 b) $P(x > 34,000) \approx 0.0001$

Work Step by Step

$\mu$ =30,800, $\sigma$ = 5,600, n =45 to find probabilities when applying the central limit theorem use z = $\frac{x - \mu}{\sigma/\sqrt n}$ where $\mu$ = $\mu_{\bar{x}}$ $\mu$ = 30,800 and $\frac{\sigma}{\sqrt n}$ \approx 834.799 PART A i) $P(x < 30,000) = P(z< \frac{30,000 - 30,800}{834.799}) \approx P(z < -0.96)$ ii) $P( z < -0.96) = 0.1685$ PART B i) $P(x > 34,000) = P(z> \frac{34,000 - 30,800}{834.799}) \approx P(z > 3.83)$ ii) $P(z>3.83) = 1 - P(z<3.83) \approx 1-0.9999 \approx 0.0001$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.