Elementary Statistics: Picturing the World (6th Edition)

Published by Pearson
ISBN 10: 0321911210
ISBN 13: 978-0-32191-121-6

Chapter 5 - Normal Probability Distributions - Review Exercises - Page 289: 60

Answer

a) $P(x < 50,000) = 0.2451$ b) P(x > 53,500) = 0.0132

Work Step by Step

$\mu$ =50,830, $\sigma$ = 8,520, n =50 to find probabilities when applying the central limit theorem use z = $\frac{x - \mu}{\sigma/\sqrt n}$ where $\mu$ = $\mu_{\bar{x}}$ $\mu$ = 50,830 and $\frac{\sigma}{\sqrt n}$ = $\frac{8520}{\sqrt 50}$ $\approx 1,204.910$ PART A i) $P(x < 50,000) = P(z< \frac{50,000 - 50,830}{1,204.910}) \approx P(z < -0.69)$ ii) $P(x < 50,000)$= $P( z < -0.69) = 0.2451$ PART B i) $P(x > 53,500) = P(z> \frac{53,500 - 50,830}{1,204.810}) \approx P(z > 2.22)$ ii) $P(z>2.22) = 1 - P(z<2.22) = 1-0.9868 = 0.0132$
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