## Elementary Statistics (12th Edition)

$0.12505\pm 0.06095.$
$\hat{p}$ is the sample average of the boundaries, hence:$\hat{p}=\frac{0.0641+0.186}{2}=0.12505.$ E is half of the confidence interval, hence:$E=\frac{0.186-0.0641}{2}=0.06095$, hence the confidence interval:$0.12505\pm 0.06095.$