Answer
$0.0799-0.0531$
Work Step by Step
$\hat{p}$ is the sample average of the boundaries, hence:$\hat{p}=\frac{0.0268+0.133}{2}=0.0799.$
E is half of the confidence interval, hence:$E=\frac{0.133-0.0268}{2}=0.0531$, hence the confidence interval: $0.0799-0.0531$
