Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 3 - Statistics for Describing, Exploring, and Comparing Data - 3-3 Measures of Variation - Basic Skills and Concepts: 18

Answer

Variance:15.55 Standard deviation:3.94 Range:16.

Work Step by Step

By using the results from before: $\mu=1.89.$ Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(11-1.89)^2+(3-1.89)^2+...+(2-1.89)^2}{18}=15.55.$ Standard deviation=$\sqrt{variance}=\sqrt{15.55}=3.94$ Range=maximum value-minimum value=$11-(-5)=16$.
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.