Elementary Statistics (12th Edition)

Published by Pearson
ISBN 10: 0321836960
ISBN 13: 978-0-32183-696-0

Chapter 3 - Statistics for Describing, Exploring, and Comparing Data - 3-3 Measures of Variation - Basic Skills and Concepts - Page 108: 14

Answer

Variance:0.13. Standard deviation:0.36 Range:1.15.

Work Step by Step

By using the results from before: $\mu=0.7186.$ Variance=$\frac{\sum (x-\mu)^2}{n}=\frac{(0.56-0.7186)^2+(0.75-0.7186)^2+...+(0.88-0.7186)^2}{7}=0.13.$ Standard deviation=$\sqrt{variance}=\sqrt{0.13}=0.36$ Range=maximum value-minimum value=$1.25-0.1=1.15$.
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