Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 5 - Review - Exercises - Page 464: 73

Answer

$y=-50cos(8\pi t)$

Work Step by Step

Given $f=4,2a=100$, since the mass is at its lowest point when t = 0, we should use a $-cos$ function as $y=-a\cdot cos(\omega t)$ with $\omega=2\pi f=8\pi$ The motion function becomes $y=-50cos(8\pi t)$
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