Precalculus: Mathematics for Calculus, 7th Edition

Published by Brooks Cole
ISBN 10: 1305071751
ISBN 13: 978-1-30507-175-9

Chapter 5 - Review - Exercises - Page 464: 54

Answer

Amplitude is 80 period is $\frac{2\pi}{3}$ Phase is $3$ Horizontal shift is $\frac{\pi}{2}$

Work Step by Step

Using the base form $y=a\cdot $sin$(k(x-b))$, one can find the data. The amplitude is $|a|$ which is $80$ in this example. The period is found using $\frac{2\pi}{k}$, so $\frac{2\pi}{3}$. The phase is $k$, so it is $3$. And the horizontal shift is represented by $b$, which, in this case, is $\frac{\pi}{2}$.
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