Answer
$\lim _{x\rightarrow 1^{+}}\sqrt {x-1}=0$
Work Step by Step
As we see from table and graph when x gets close to 1 from positive side
$\lim _{x\rightarrow 1^{+}}\sqrt {x-1}=0$
Precalculus: Mathematics for Calculus, 7th Edition
by Stewart, James; Redlin, Lothar; Watson, Saleem
Published by
Brooks Cole
ISBN 10:
1305071751
ISBN 13:
978-1-30507-175-9
Chapter 13 - Review - Exercises - Page 941: 5
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