Answer
$\lim _{t\rightarrow -1}\dfrac {t+1}{t^{3}-t}=0.5$
Work Step by Step
As we see from the graph and table when x gets close to $-1$ then
$\lim _{t\rightarrow -1}\dfrac {t+1}{t^{3}-t}=0.5$ gets close to $0.5$
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