Answer
(a) Focus: $F(0,-3)$
Directrix: $y=3$
$Focal~diameter=12$
(b)
Work Step by Step
Equation of a parabola with vertical axis: $x^2=4py$
$x^2+12y=0$
$x^2=-12y$
$4p=-12$
$p=-3$
Focus: $F(0,p)=F(0,-3)$
Directrix: $y=-p=3$
$Focal~diameter=|4p|=12$