Answer
(a) Focus: $F(\frac{1}{36},0)$
Directrix: $x=\frac{1}{36}$
$Focal~diameter=\frac{1}{9}$
(b)
Work Step by Step
Equation of a parabola with horizontal axis: $y^2=4px$
$9x=y^2$
$y^2=9x$
$4p=9$
$p=\frac{9}{4}$
Focus: $F(p,0)=F(\frac{9}{4},0)$
Directrix: $x=-p=-\frac{9}{4}$
$Focal~diameter=|4p|=9$
