Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.5 Rational Expressions - R.5 Exercises: 38

Answer

$\color{blue}{\dfrac{7}{y}}$

Work Step by Step

Factor the binomials, then cancel common factors to obtain: $\require{cancel} =\dfrac{y^2(y+1)}{7} \cdot \dfrac{7(7)}{y^3(y+1)} \\=\dfrac{\cancel{y^2}\cancel{(y+1)}}{\cancel{7}} \cdot \dfrac{7\cancel{(7)}}{\cancel{y^3}y\cancel{(y+1)}} \\=\color{blue}{\dfrac{7}{y}}$
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