Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter R - Review of Basic Concepts - R.5 Rational Expressions - R.5 Exercises: 30

Answer

$\color{blue}{\dfrac{2y+1}{y+1}}$

Work Step by Step

Factor the numerator and the denominator then cancel the common factors to obtain: $\require{cancel} =\dfrac{(3y+4)(2y+1)}{(3y+4)(y+1)} \\=\dfrac{\cancel{(3y+4)}(2y+1)}{\cancel{(3y+4)}(y+1)} \\=\color{blue}{\dfrac{2y+1}{y+1}}$
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