Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 8 - Application of Trigonometry - 8.4 Algebraically Defined Vectors and the Dot Product - 8.4 Exercises - Page 790: 57

Answer

$36.87^{\circ}$

Work Step by Step

To obtain the angle $\theta$ between two non-zero vectors $a$ and $b$, we will use the following formula such as: $ \theta =\cos^{-1} (\dfrac{\overrightarrow{a} \cdot \overrightarrow{ b} }{|a| |b|})$ We have: $\overrightarrow{a} \cdot \overrightarrow{ b}= (3)(0) +(4) (1) = 4$ and $|a|=\sqrt {(3)^2+(4)^2}=\sqrt {25}=5 ; |b|=\sqrt {(0)^2+(1)^2}=1$ Therefore, $ \theta =\cos^{-1} (\dfrac{4}{ 5})= 36.87^{\circ}$
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