Answer
$\lt -1.93, 2.30 \gt $
Work Step by Step
Let $v$ is a vector that has a magnitude $|v|$ and the direction angle of $\theta$.
The magnitude of horizontal component is given by: $v_x=|v| \cos \theta= 3 \cos 130^{\circ}= -1.93$
And
The magnitude of vertical component is given by: $v_y=|v| \sin \theta= 3 \sin 130^{\circ}= 2.30$
Thus, $v=\lt -1.93, 2.30 \gt $