Answer
$$A = {30^ \circ },\,\,\,\,B = {56^ \circ },\,\,\,C = {94^ \circ }$$
Work Step by Step
$$\eqalign{
& a = {\text{3}}.0{\text{ ft}},\,\,\,\,b = {\text{5}}.0{\text{ ft}},\,\,\,\,c = {\text{6}}.0{\text{ ft}} \cr
& {\text{Use the law of cosines to solve for any angle of the triangle}} \cr
& {c^2} = {a^2} + {b^2} - 2ab\cos C \cr
& {\text{Solve for cos }}C \cr
& \cos C = \frac{{{a^2} + {b^2} - {c^2}}}{{2ab}} \cr
& {\text{Substitute}} \cr
& \cos C = \frac{{{{\left( {{\text{3}}.0} \right)}^2} + {{\left( {{\text{5}}.0} \right)}^2} - {{\left( {{\text{6}}.0} \right)}^2}}}{{2\left( {{\text{3}}.0} \right)\left( {{\text{5}}.0} \right)}} \cr
& {\text{Use a calculator}} \cr
& \cos C = - \frac{1}{{15}} \cr
& {\text{Use the inverse cosine function}} \cr
& C \approx {94^ \circ } \cr
& \cr
& {\text{Use the Law of sines to find the angle of }}B \cr
& \frac{{\sin B}}{b} = \frac{{\sin C}}{c} \cr
& \sin B = \frac{{b\sin C}}{c} \cr
& \sin B = \frac{{5\sin \left( {{{94}^ \circ }} \right)}}{6} \cr
& {\text{Use a calculator}} \cr
& \sin B \approx 0.83130337 \cr
& {\text{Use the inverse sine function}} \cr
& B \approx {56^ \circ } \cr
& \cr
& {\text{Calculate }}A \cr
& A = {180^ \circ } - B - C \cr
& A = {180^ \circ } - {56^ \circ } - {94^ \circ } \cr
& A = {30^ \circ } \cr
& \cr
& {\text{Answer}} \cr
& A = {30^ \circ },\,\,\,\,B = {56^ \circ },\,\,\,C = {94^ \circ } \cr} $$
