Answer
$\tan \theta $
Work Step by Step
$\tan \left( 180^{0}+\theta \right) =\dfrac {\tan 180+\tan \theta }{1-\tan 180\tan \theta }=\dfrac {0+\tan \theta }{1-0\times \tan \theta }=\tan \theta $
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 7 - Trigonometric Identities and Equations - 7.3 Sum and Difference Identities - 7.3 Exercises - Page 680: 76
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