Answer
$\dfrac {1+\tan x}{1-\tan x}$
Work Step by Step
$\tan \left( \dfrac {\pi }{4}+x\right) =\dfrac {\tan \dfrac {\pi }{4}+\tan x}{1-\tan \dfrac {\pi }{4}\tan x}=\dfrac {1+\tan x}{1-\tan x}$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 7 - Trigonometric Identities and Equations - 7.3 Sum and Difference Identities - 7.3 Exercises - Page 680: 72
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