Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.3 Sum and Difference Identities - 7.3 Exercises - Page 678: 4

Answer

E

Work Step by Step

$\sin \left( \dfrac {\pi }{2}-x\right) =\sin \dfrac {\pi }{2}\cos x-\cos \dfrac {\pi }{2}\sin x=1\times \cos x-0\times \sin x=\cos x\Rightarrow 4\rightarrow E$
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