Answer
B
Work Step by Step
$\sin \left( x-\dfrac {\pi }{2}\right) =\sin x\cos \dfrac {\pi }{2}-\cos x\sin \dfrac {\pi }{2}=\sin x\times 0-\cos x\times 1=-\cos x\Rightarrow 6\rightarrow B$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 7 - Trigonometric Identities and Equations - 7.3 Sum and Difference Identities - 7.3 Exercises - Page 678: 6
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