Answer
$\tan \theta \sin \theta $
Work Step by Step
$sec\theta -\cos \theta =\dfrac {1}{\cos \theta }-\cos \theta =\dfrac {1-\cos ^{2}\theta }{\cos \theta }=\dfrac {\sin ^{2}\theta }{\cos \theta }=\tan \theta \sin \theta $
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 7 - Trigonometric Identities and Equations - 7.1 Fundamental Identities - 7.1 Exercises - Page 659: 67
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