Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.1 Fundamental Identities - 7.1 Exercises - Page 659: 59

Answer

$\cos^2\theta$

Work Step by Step

$\sin^2\theta(\csc^2\theta-1)$ $=\sin^2\theta*\cot^2\theta$ $=\sin^2\theta*\frac{\cos^2\theta}{\sin^2\theta}$ $=\cos^2\theta$
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