## Precalculus (6th Edition)

$-\dfrac {\sqrt {117}}{11}$
$sec\theta =\dfrac {1}{\cos \theta }=\dfrac {11}{4}$ (positive) $\cot \theta < 0$ ( negative) So angle is located in quadrant 4(sine is negative in quadrant 4) $\Rightarrow \sin \theta =-\sqrt {1-\cos ^{2}\theta }=-\sqrt {1-\left( \dfrac {4}{11}\right) ^{2}}=-\dfrac {\sqrt {117}}{11}$