Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.1 Fundamental Identities - 7.1 Exercises: 19

Answer

$-\dfrac {\sqrt {117}}{11}$

Work Step by Step

$sec\theta =\dfrac {1}{\cos \theta }=\dfrac {11}{4}$ (positive) $\cot \theta < 0$ ( negative) So angle is located in quadrant 4(sine is negative in quadrant 4) $\Rightarrow \sin \theta =-\sqrt {1-\cos ^{2}\theta }=-\sqrt {1-\left( \dfrac {4}{11}\right) ^{2}}=-\dfrac {\sqrt {117}}{11}$
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