Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 7 - Trigonometric Identities and Equations - 7.1 Fundamental Identities - 7.1 Exercises: 13

Answer

$\sin \theta =-\dfrac {5}{\sqrt {26}}$

Work Step by Step

$\sin \theta =\pm \dfrac {1}{\sqrt {1+\cot ^{2}\theta }}=\pm \dfrac {1}{\sqrt {1+\left( -\dfrac {1}{5}\right) ^{2}}}=\pm \dfrac {5}{\sqrt {26}}$ In quadrant 4 sine function is negative so $\sin \theta =-\dfrac {5}{\sqrt {26}}$
Update this answer!

You can help us out by revising, improving and updating this answer.

Update this answer

After you claim an answer you’ll have 24 hours to send in a draft. An editor will review the submission and either publish your submission or provide feedback.