Answer
${2\pi}$
Work Step by Step
Given the angular speed of point P as $\omega=1\ rad/sec$, to move around the entire unit circle or $\theta=2\pi$ angle, the time is $t=\frac{\theta}{\omega}=\frac{2\pi}{1}=2\pi\ sec$
Precalculus (6th Edition)
by Lial, Margaret L.; Hornsby, John; Schneider, David I.; Daniels, Callie
Published by
Pearson
ISBN 10:
013421742X
ISBN 13:
978-0-13421-742-0
Chapter 6 - The Circular Functions and Their Graphs - 6.2 The Unit Circle and Circular Functions - 6.2 Exercises - Page 587: 9
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