Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 6 - The Circular Functions and Their Graphs - 6.2 The Unit Circle and Circular Functions - 6.2 Exercises: 1

Answer

The missing coordinates are: $90^o: (0, 1)$ $60^o: (\frac{1}{2}, \frac{\sqrt3}{2})$ $45^o: (\frac{\sqrt2}{2}, \frac{\sqrt2}{2})$ $30^o: (\frac{\sqrt3}{2}, \frac{1}{2})$ $0^o: (1, 0)$

Work Step by Step

Using Figure 13 on page 579 of this book, the coordinates of the points indicated are: $90^o: (0, 1)$ $60^o: (\frac{1}{2}, \frac{\sqrt3}{2})$ $45^o: (\frac{\sqrt2}{2}, \frac{\sqrt2}{2})$ $30^o: (\frac{\sqrt3}{2}, \frac{1}{2})$ $0^o: (1, 0)$
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