Precalculus (6th Edition)

Published by Pearson
ISBN 10: 013421742X
ISBN 13: 978-0-13421-742-0

Chapter 5 - Trigonometric Functions - 5.1 Angles - 5.1 Exercises - Page 506: 128

Answer

Difference to the nearest minute= $00^{\circ}05'$ Difference to the nearest hundredth= $0.08^{\circ}$

Work Step by Step

$74.25^{\circ}=74^{\circ}+0.25(60')$ $=74^{\circ}+15'=74^{\circ}15'$ $74^{\circ}20'=74^{\circ}+\frac{20}{60}^{\circ}$ $=74^{\circ}+0.3333^{\circ}=74.3333^{\circ}$ Difference to the nearest minute= $74^{\circ}20'-74^{\circ}15'=00^{\circ}05'$ Difference to the nearest hundredth= $74.3333^{\circ}-74.25^{\circ}=0.08^{\circ}$
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